tjsmudger 2 Posted December 15, 2010 Report Share Posted December 15, 2010 Random question here but in my drunken stupor, I thought this could be belting. If I brim my golf vr6 and left it outside my house with the engine running and here comes the question, how long in time before my petrol tank runs clean of fuel. Bearing in mind the engine running at idle. There we go, I'm sure someone will have a rough or accurate idea. Peace and love to mankind, ho ho ho ho!!! P.s, I know some funny guys will say it wont last lon goutside your house long with the keys in the ignition!! It's a theoretical question! Ho ho ho, little donkey and all that. Link to post Share on other sites
craggsy 91 Posted December 16, 2010 Report Share Posted December 16, 2010 A quick google says about 1 hr per gallon ish. Obviously there are contributing factors but im sure some bright spark can do the maths, but not me Link to post Share on other sites
craggsy 91 Posted December 16, 2010 Report Share Posted December 16, 2010 Sorry got me googling that quite a bit now.Seeing figures for a GTI, dont know what tho, saying 1.2 litres per hour on a 55 litre tank. So about 45 hours. Link to post Share on other sites
Wudy 0 Posted December 16, 2010 Report Share Posted December 16, 2010 Well taking a idle consumption of 0.3 gallons per hour (I don't know what it is for a VR, but research shows that what's a 2.5 V6 does so close enough). Say it's 55 litres in the tank.55 litres = 12 gallonsAt 0.3 gallons/hour I make that to be about 40 hours.So yea, around 40/45 hours. Anyone going to give it a go? Link to post Share on other sites
raddo_tom 0 Posted December 16, 2010 Report Share Posted December 16, 2010 How long before....It overheats.Blows up.Gets bored and turns off??Scary questions when drunk.... Link to post Share on other sites
Ian_rogers 0 Posted December 16, 2010 Report Share Posted December 16, 2010 I've thought about this before but never got an answerMPG would be crap lol Link to post Share on other sites
tjsmudger 2 Posted December 16, 2010 Author Report Share Posted December 16, 2010 I WONT be attempting this, not with the price of fuel nowadays!! Better option would be to see how much 'fuel' I could get in myself before I pass out or get bored! Sore head this morn.... Roll on the Arrers tonight!!! Barney 14/1 blue square, got to be worth a punt at those odds!! Link to post Share on other sites
Apollo 0 Posted December 16, 2010 Report Share Posted December 16, 2010 The mathematical answer….If we start with a full tank of 55 litres of C8H18 and the idle speed is 800 RPM ……Take the 55 litres of C8H18 and divide it by the WGAF (Who Gives A F*ck) factor you where drunk when you thought of this question and I am not drunk enough to attempt to answer it as my head hurts.Then take said 55 litres of C8H18l add one very sober driver with a heavy right foot. This will result in 55 litres becoming (C6H6)+(Cd)+ (CO2)+ (C O)+ (NOx)+ (SO2) in a lot less than the estimated 40-45 hours at idle speed.The result will be one human being topped up with C9H13NO3. Link to post Share on other sites
Lukey. 381 Posted December 16, 2010 Report Share Posted December 16, 2010 wouldnt that be more the chemistry answer? :-p Link to post Share on other sites
Apollo 0 Posted December 16, 2010 Report Share Posted December 16, 2010 Good point......DOH! Link to post Share on other sites
The Monk 50 Posted December 16, 2010 Report Share Posted December 16, 2010 Nice try though, Apollo I could work it out IF I could be bother to spend 20ish minutes.Though I'd have to figure out 14.7:1, swept volume ect ect I used 800rpm and 2792cc as base.36.2 hours on 55 litresPassat 2771cc 62L tank@800rpm41.1 hours. Link to post Share on other sites
Recommended Posts